0=(x^2+2x-600)

Solution for 0=(x^2+2x-600) equation:

0=(x^2+2x-600)

We move all terms to the left:

0-((x^2+2x-600))=0

We add all the numbers together, and all the variables

-((x^2+2x-600))=0


We calculate terms in parentheses: -((x^2+2x-600)), so:

(x^2+2x-600)

We get rid of parentheses

x^2+2x-600

Back to the equation:

-(x^2+2x-600)


We get rid of parentheses

-x^2-2x+600=0

We add all the numbers together, and all the variables

-1x^2-2x+600=0

a = -1; b = -2; c = +600;
Δ = b2-4ac
Δ = -22-4·(-1)·600
Δ = 2404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2404}=\sqrt{4*601}=\sqrt{4}*\sqrt{601}=2\sqrt{601}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{601}}{2*-1}=\frac{2-2\sqrt{601}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{601}}{2*-1}=\frac{2+2\sqrt{601}}{-2}
$